3x+4x=7x^2/2

Solution for 3x+4x=7x^2/2 equation:

3x+4x=7x^2/2

We move all terms to the left:

3x+4x-(7x^2/2)=0

We add all the numbers together, and all the variables

7x-(7x^2/2)=0

We get rid of parentheses

-7x^2/2+7x=0

We multiply all the terms by the denominator


-7x^2+7x*2=0

Wy multiply elements

-7x^2+14x=0

a = -7; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-7)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-7}=\frac{-28}{-14}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-7}=\frac{0}{-14}
=0
$